16t^2-1600t+14400=0

Solution for 16t^2-1600t+14400=0 equation:

16t^2-1600t+14400=0

a = 16; b = -1600; c = +14400;
Δ = b2-4ac
Δ = -16002-4·16·14400
Δ = 1638400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1638400}=1280$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1600)-1280}{2*16}=\frac{320}{32}
=10
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1600)+1280}{2*16}=\frac{2880}{32}
=90
$